A) \[10\,m{{s}^{-2}}\]
B) \[6.5\,m{{s}^{-2}}\]
C) \[2.5\,m{{s}^{-2}}\]
D) \[1\,m{{s}^{-2}}\]
Correct Answer: C
Solution :
For the rolling object on inclined plane \[a=\frac{g\sin \theta }{1+\frac{I}{m{{r}^{2}}}}=\frac{g\sin 30{}^\circ }{1+1}=2.5\,m{{s}^{-2}}\]You need to login to perform this action.
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