A) reflexive but not symmetric
B) symmetric only
C) reflexive and transitive
D) equivalence
Correct Answer: B
Solution :
\[aRa\], then G.C.D of and a is a. \[\therefore \] r is not reflexive. (ii) \[aRb\Rightarrow bRa\] If G.C.D of a and b is 2, then G.C.D. of b and a is also 2. \[\Rightarrow \] R is symmetric. (iii) \[aRb,\,\,bRc\,aRc\] e.g. \[4R2,\,\,2R8\,4R8\] \[\Rightarrow \] R is not transitive.You need to login to perform this action.
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