\[y+z=a+2x\] |
\[x+z=b+2y\] |
\[x+y=c+2z\] |
A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
\[\left. \begin{matrix} y+z=a+2x \\ x+z=b+2y \\ x+y=c+2z \\ \end{matrix} \right\}\] adding \[a+b+c=0\] Given 16a - 4b + c = 0 \[\therefore \,\,x=-4\] \[a{{x}^{2}}+bx+c\left\langle \begin{align} & 1 \\ & -4 \\ \end{align} \right.\] Sum of roots = - 3 \[\Rightarrow \] absolute value of sum of roots \[=\,|-3|=3\]You need to login to perform this action.
You will be redirected in
3 sec