A) \[3\,\mu C\]
B) \[9\,\mu C\]
C) \[6\,\mu C\]
D) \[12\,\mu C\]
Correct Answer: B
Solution :
As \[{{S}_{2}}\] is open, hence \[{{C}_{1}}\] & \[{{C}_{3}}\] are in series, also \[{{C}_{2}}\] & \[{{C}_{4}}\] are in series combination, \[Q=\frac{3}{4}\times V=\frac{3}{4}\times 12=9\mu C;\] Charge on \[C_{1}^{'}=9\mu C;\] Charge on \[C_{2}^{'}=\frac{4}{3}\times 12=16\mu C\] Hence, charge on \[{{C}_{1}}\] and \[{{C}_{3}}\] is \[9\mu C,\] as both are in series combination.You need to login to perform this action.
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