A) \[\frac{\pi }{3}\]
B) \[\frac{2\pi }{3}\]
C) \[\frac{5\pi }{6}\]
D) \[\frac{7\pi }{6}\]
Correct Answer: C
Solution :
\[I={{I}_{0}}\,\sin (\omega t+\phi );\] \[E={{E}_{0}}\,\sin (\omega t+\phi );\] \[I=4\sin \omega t;\] \[E=100\sin \left( \omega t+\frac{\pi }{2}+\frac{\pi }{3} \right)\] Phase diff. between I and \[E=\frac{\pi }{3}+\frac{\pi }{2}=\frac{5\pi }{6}\]You need to login to perform this action.
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