| Statement-1: Orbital velocity of a satellite is greater than its escape velocity. |
| Statement-2: Orbit of a satellite is within the gravitational field of earth whereas escaping is beyond the gravitational field of earth. |
A) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
B) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
C) Statement-1 is true, Statement-2 is false.
D) Statement-1 is false, Statement-2 is true.
Correct Answer: D
Solution :
The orbital velocity, if a satellite close to earth is \[{{v}_{0}}=\sqrt{g{{R}_{e}}},\] While the escape velocity for a body thrown from the earth's surface is \[{{v}_{e}}=\sqrt{2g{{R}_{e}}}\] Thus, \[\frac{{{v}_{0}}}{{{v}_{e}}}=\frac{\sqrt{g{{R}_{e}}}}{\sqrt{2g{{R}_{e}}}}=\frac{1}{\sqrt{2}}\]or \[{{v}_{e}}=\sqrt{2}{{v}_{0}}\]i.e., if the orbital velocity of a satellite revolving close to the earth happens to increase to \[\sqrt{2}\]times, the satellite would escape.
You need to login to perform this action.
You will be redirected in
3 sec
