JEE Main & Advanced Sample Paper JEE Main Sample Paper-38

  • question_answer 47) A straight section \[PO\] of a circuit lies along the x-axis from \[x=-a/2\]to \[x=+a/2,\]and carries a steady current 'T'. The magnitude of magnetic field due to the section PO at a point to \[y=+a\] will be

    A)  Proportional to a      

    B)  Proportional to a2

    C)  Proportional to I/a     

    D)  Equal to zero

    Correct Answer: C

    Solution :

     \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{I}{a}(\sin \theta +\sin \theta )=\frac{{{\mu }_{0}}I\sin \theta }{2\pi a}\]B at any point on Y axis is inversely proportional to a.

adversite



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