A) \[20\,A\]
B) \[10\,A\]
C) \[5\,A\]
D) \[5\sqrt{2}\,A\]
Correct Answer: D
Solution :
\[{{i}_{R}}=\frac{{{V}_{0}}}{R}=\frac{100}{20}=5,\,{{i}_{L}}=\frac{{{V}_{0}}}{{{X}_{L}}}=\frac{100}{10}=10\] and\[{{i}_{C}}=\frac{{{V}_{0}}}{{{X}_{C}}}=\frac{100}{20}=5\] Current, \[i=\sqrt{i_{R}^{2}+{{({{i}_{C}}-{{i}_{L}})}^{2}}}=\sqrt{{{5}^{2}}+{{5}^{2}}}=5\sqrt{2}amp.\].
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