A) 3 m/s
B) 6 m/s
C) \[3\sqrt{2}\,\text{m/s}\]
D) \[2\sqrt{3}\,\text{m/s}\]
Correct Answer: C
Solution :
Along initial direction, \[{{v}_{x}}=3\text{m/s}\text{.}\] Along perpendicular direction \[{{v}_{y}}=0+1\times 3=3\,\,\text{m/s}\] \[\therefore \] \[|v|=\sqrt{v_{x}^{2}+v_{y}^{2}}=3\sqrt{2}\,\text{m/s}\]You need to login to perform this action.
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