A) 200 m/s each
B) 145 m/s and 256 m/s
C) 536 m/s and 320 m/s
D) None of the above
Correct Answer: D
Solution :
Three guns are fired towards the centre of circle as shown in figure. Since, total final momentum is zero, and no external force is acting on the system. So total initial momentum should also be zero. So, \[\overrightarrow{{{P}_{1}}}+\overrightarrow{{{P}_{2}}}+\overrightarrow{{{P}_{3}}}=0\] Three vectors, which are at an angle of \[120{}^\circ \] leads to zero resultant if and only, if they have same magnitude. So,\[4.50{{v}_{1}}=2.5\times 575=4.5{{v}_{2}}\] After solving, we will get \[{{v}_{1}}\]and \[{{v}_{2}}\]be 320 m/s.You need to login to perform this action.
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