A) 1 : 2
B) 1 : 1
C) 1 : 16
D) 15 : 16
Correct Answer: D
Solution :
Let the mass of ethane = hydrogen \[=x\,g\] \[\therefore \] Moles of ethane \[=\frac{x}{30}\]and moles of hydrogen \[=\frac{x}{2}\] \[\therefore \] \[{{p}_{{{H}_{2}}}}=\frac{\frac{x}{2}}{\frac{x}{2}+\frac{x}{30}}\times {{p}_{total}}=\frac{1}{2}\times \frac{30}{16}p=\frac{15}{16}p\]You need to login to perform this action.
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