• # question_answer Using the following Latimer diagram for bromine,$pH=0;\,\,Br{{O}_{2}}\xrightarrow{1.82\,V}\,BrO_{3}^{-}\xrightarrow{1.50\,V}\,$ $HBr{{O}_{2}}\xrightarrow{1.595\,V}\,B{{r}_{2}}\xrightarrow{1.652\,V}B{{r}^{-}}$ The species undergoing dispropotionation is A)  $Br{{O}_{4}}$                    B)  $BrO_{3}^{-}$ C)  $HBrO$                     D)  $B{{r}_{2}}$

Solution :

Hbr O will undergo disproportionation, because the potential to the left of it is less than that to the right.

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