A) it is 1.7% weight by volume
B) it is 1 N
C) Both [a] and [b]
D) None of these
Correct Answer: C
Solution :
\[2{{H}_{2}}{{O}_{2}}\xrightarrow{\,}\,2{{H}_{2}}O+{{O}_{2}}\] 5.6 volume means 1 mL of HOg solution gives \[5.6\,\,mL\,{{O}_{2}}\] at STP. \[\because \] 22400 mL \[{{O}_{2}}\] at NTP is obtained from \[68\,g\,{{H}_{2}}{{O}_{2}}\]. \[\therefore \] 5.6 mL \[{{O}_{2}}\] at NTP is obtained from \[\frac{68\times 5.6}{22400}\]. \[{{H}_{2}}{{O}_{2}}=0.017\,g\,{{H}_{2}}{{O}_{2}}\] \[\therefore \] It is 1.7% And normally \[\frac{\text{Volume}\,\text{strength}}{5.6}=1N\]
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