A) \[\alpha =\beta \]
B) \[\alpha >\beta \]
C) \[\alpha <\beta \]
D) All are possible, depending upon \[\alpha \]
Correct Answer: A
Solution :
By analysis the diagram and with the help of laws of reflection and refraction. \[\alpha +90-{{\theta }_{1}}+90-\theta \] \[=90-\alpha +90+{{\theta }_{2}}+\theta ={{180}^{o}}\] \[\Rightarrow \] \[\alpha -{{\theta }_{1}}-\theta -\alpha +{{\theta }_{2}}+\theta =0\] and \[\alpha ={{\theta }_{2}}+\theta \] \[\Rightarrow \] \[{{\theta }_{1}}={{\theta }_{2}}\] \[\Rightarrow \] \[\alpha =\beta \]You need to login to perform this action.
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