A) \[10\,\mu C\]
B) \[20\,\mu C\]
C) \[25\,\mu C\]
D) \[30\,\mu C\]
Correct Answer: A
Solution :
When switch S is closed, the charge on sphere A will be redistributed on A and C in the ratio of their capacitances, \[\frac{{{q}_{1}}}{q-{{q}_{1}}}=\frac{4\pi {{\varepsilon }_{0}}\,\left( \frac{ab}{b-a} \right)}{4\pi {{\varepsilon }_{0}}C}\] \[{{q}_{1}}=\frac{q\,ab}{ab+bc-ca}\] Taking \[q=30\,\mu C\] \[a=1\,cm,\] \[b=2\,cm,\] \[c=1\,cm\] We get, \[{{q}_{1}}=20\,\,\mu C\] \[\therefore \] \[q-{{q}_{1}}=30-20=10\,\mu C\]You need to login to perform this action.
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