JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    One mole of a non - ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) \[\to \] (4.0 atm, 5.0 L, 245 K) with a change in internal energy, \[\Delta E=30.0\text{ }L-atm.\]The change in enthalpy \[(\Delta E)\] of the process in L-atm is

    A)  40.0                      

    B)  42.0     

    C)  44.0

    D)  not defined, because pressure is not constant

    Correct Answer: C

    Solution :

    \[\Delta H=\Delta U+\Delta (pV)\] \[=30+2(5-3)+5(4-2)=44\,L\,atm\]

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