• question_answer One mole of a non - ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) $\to$ (4.0 atm, 5.0 L, 245 K) with a change in internal energy, $\Delta E=30.0\text{ }L-atm.$The change in enthalpy $(\Delta E)$ of the process in L-atm is A)  40.0                       B)  42.0      C)  44.0 D)  not defined, because pressure is not constant

$\Delta H=\Delta U+\Delta (pV)$ $=30+2(5-3)+5(4-2)=44\,L\,atm$