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JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    If \[a\ne 0\And \] the line \[2bx+3cy+4d=0\] passes through the point of intersection of parabola \[{{y}^{2}}=4ax\] and \[{{x}^{2}}=4ay,\]then

    A) \[{{d}^{2}}+{{(3b-2c)}^{2}}=0\] 

    B) \[{{d}^{2}}+{{(3b+2c)}^{2}}=0\]

    C) \[{{d}^{2}}+{{(2b-3c)}^{2}}=0\] 

    D) \[{{d}^{2}}+{{(2b+3c)}^{2}}=0\]

    Correct Answer: D

    Solution :

    Two given parabola intersect at (0,0) and (4a, 4a). So, the common chord is y = x. On comparing y = x with given line, we get \[\frac{2b}{1}=\frac{3c}{-1}=\frac{4d}{0}\]\[\Rightarrow \]d = 0 and \[2b=3c=0\]


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