A) \[2.7x{{10}^{4}}C\]
B) \[8.8x{{10}^{4}}C\]
C) \[18.3x{{10}^{4}}C\]
D) \[1.7x{{10}^{4}}C\]
Correct Answer: A
Solution :
\[W=\frac{A}{nF}lt\]or\[\rho \times V=\frac{A}{nF}Q\] \[Q=\frac{\rho \times area\times thickness}{A}\times nF\] \[=\frac{8.94\times 10\times 10\times {{10}^{-2}}\times 2\times 96500}{63.6}=2.7\times {{10}^{4}}C\]
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