KVPY Sample Paper KVPY Stream-SX Model Paper-12

  • question_answer
    The general values of \[\theta \] satisfying the equation \[2{{\sin }^{2}}\theta -3\sin \theta -2=0\]is

    A) \[n\pi +{{(-1)}^{n}}\pi /6\]

    B) \[n\pi +{{(-1)}^{n}}\pi /2\]

    C) \[n\pi +{{(-1)}^{n}}5\pi /6\]

    D) \[n\pi +{{(-1)}^{n}}7\pi /6\]

    Correct Answer: D

    Solution :

    The given equation is
    \[2{{\sin }^{2}}\theta -3\sin \theta -2=0\]
    \[\Rightarrow \]\[(2\sin \theta +1)(\sin \theta -2)=0\]
    \[\Rightarrow \]\[\sin \theta =-\frac{1}{2}\]
                \[\left[ \because \sin \theta -2=0\operatorname{is}\,not\,possible \right]\]
    \[\Rightarrow \]\[\sin \theta =\sin (-\pi /6)=\sin (7\pi /6)\]
    \[\Rightarrow \]\[\theta =n\pi +{{(-1)}^{n}}(-\pi /6)\]
           \[=n\pi +{{(-1)}^{n}}7\pi /6\]
    \[\Rightarrow \]Thus, \[\theta =n\pi +{{(-1)}^{n}}7\pi /6\]


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