A) Val-Galy-Phe-Val-Al-a-Val
B) Val-Ala-Phe-Val-Gly-Val
C) Val-Gly-Ala-Val-Phe-Val
D) Val-Phe-Val-Ala-Gly-Val
Correct Answer: A
Solution :
\[Val\text{-}\,Gly\text{-}Phe\text{-}Val\text{-}Ala\text{-}Val\] Random hydrolysis gives Ala-Val dipeptide fragment, which indicates the connected presence of Ala and Val. Thus, the correct sequence is given in option [a].You need to login to perform this action.
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