A) 11
B) 10
C) 1
D) None of These
Correct Answer: C
Solution :
It is possible if equation becomes identity \[\Rightarrow {{a}^{2}}-3a+2=0\] \[\Rightarrow a=1,\,\,2\] \[\Rightarrow {{a}^{2}}-4a+3=0\] \[\Rightarrow a=1,\,\,3\] \[\Rightarrow {{a}^{2}}-6a+5=0\] \[\Rightarrow a=1,\,\,5\] Common value of a is 1.You need to login to perform this action.
You will be redirected in
3 sec