A) 50
B) 10
C) 5
D) None
Correct Answer: C
Solution :
\[k-1+x=t,\]\[dx=dt\] \[\sum\limits_{k=1}^{10}{\int_{k-1}^{k}{f(t)dt=\int\limits_{0}^{1}{+\int\limits_{0}^{2}{+....+\int\limits_{9}^{10}{=\int\limits_{0}^{10}{f(t)\,\,dt=5}}}}}}\]You need to login to perform this action.
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