• # question_answer If ${{K}_{sp}}$Ag $A{{g}_{2}}C{{O}_{3}}$ is $8\times {{10}^{-12}},$the molar solubilty of $A{{g}_{2}}C{{O}_{3}}$ in $AgN{{O}_{3}}$ is: A) $8\times {{10}^{-12}}M$ B) $8\times {{10}^{-11}}M$ C) $8\times {{10}^{-10}}M$ D) $8\times {{10}^{-13}}M$

$8\times {{10}^{-12}}={{(2S'+0.1)}^{2}}S'$ Or,        $S'=8\times {{10}^{-10}}M.$