A) 1 : 16
B) 1 : 2
C) 1 : 4
D) 1 : 8
Correct Answer: A
Solution :
\[Area\propto \pi {{(Range)}^{2}}\propto {{v}^{4}}\] \[\therefore \] \[\frac{{{A}_{1}}}{{{A}_{2}}}={{\left( \frac{1}{2} \right)}^{4}}.\]You need to login to perform this action.
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