A) 40
B) 16
C) 640
D) 410
Correct Answer: A
Solution :
\[\frac{128kg}{{{m}^{3}}}=\frac{64(2kg)}{10c{{m}^{3}}}\] |
\[=\frac{64(2kg)}{{{10}^{6}}(50c{{m}^{3}})}\times {{50}^{3}}\] |
\[=\frac{64\times 50\times 50\times 50}{100\times 100\times 100}\times \frac{2kg}{(50c{{m}^{3}})}\] \[=8\frac{(2kg)}{(50c{{m}^{3}})}.\] |
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