A) \[2m{{v}^{2}}\]
B) \[m{{v}^{2}}\]
C) \[\frac{1}{2}m{{v}^{2}}\]
D) \[\frac{3}{2}m{{v}^{2}}\]
Correct Answer: B
Solution :
Initially, kinetic energy\[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}m\frac{G{{M}_{e}}}{r}\] |
By conservation of M.E.,\[\frac{-G{{M}_{e}}m}{r}+KE=0\] |
\[KE=\frac{G{{M}_{e}}m}{r}=m{{v}^{2}}.\] |
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