A) 5.1 cm
B) 1.7 cm
C) 4 cm
D) 2.9 cm
Correct Answer: A
Solution :
\[\frac{dV}{dt}=\phi -a\sqrt{2gh}=0\](for maximum height) |
\[h=\frac{{{\phi }^{2}}}{2g{{a}^{2}}}=\frac{{{10}^{-8}}}{2\times 9.8\times {{10}^{-8}}}=5.1cm.\] |
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