A) 33%
B) 66%
C) 70%
D) 40%
Correct Answer: B
Solution :
Meq. of oxalate = Meq. of \[KMn{{O}_{4}}\] |
\[\frac{w}{88/2}\times 1000=90\times \frac{1}{20}\] |
\[\therefore \,\,{{w}_{oxalate}}=0.198g\] |
\[%\,oxalate=\frac{0.198}{0.3}\times 100=66%\] |
You need to login to perform this action.
You will be redirected in
3 sec