A) \[-4\]
B) \[-3\]
C) \[4\]
D) \[3\]
Correct Answer: A
Solution :
\[\overline{\alpha }=(\lambda -2)\overrightarrow{a}+\overrightarrow{b}\] |
\[\overrightarrow{\beta }=(4\lambda -2)\overrightarrow{a}+3\overrightarrow{b}\] |
\[\overrightarrow{\alpha }\]and \[\overrightarrow{\beta }\]are collinear |
\[\left| \begin{matrix} \lambda -2 & 1 \\ 4\lambda -2 & 3 \\ \end{matrix} \right|=0\] |
\[3\lambda -6-4\lambda +2=0\] |
\[-\lambda -4=0\] |
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