A) 3
B) 2
C) 1
D) None of these
Correct Answer: B
Solution :
Solution we have \[x=2+{{2}^{2/3}}+{{2}^{1/3}}\]\[\Rightarrow x-2={{2}^{2/3}}+{{2}^{1/3}}\]\[\Rightarrow {{(x-2)}^{3}}={{2}^{2}}+2+{{3.2}^{2/3}}{{2}^{1/3}}({{2}^{2/3}}+{{2}^{1/3}})\] |
\[\Rightarrow {{x}^{3}}-6{{x}^{2}}+12x-8=4+2+3\,\,x\,\,2\,\,x\,\,(x-2)\]\[\Rightarrow {{x}^{3}}-6{{x}^{2}}+6x=2.\] |
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