A) \[\frac{{{a}^{2}}}{{{A}^{2}}}\]
B) \[\frac{{{b}^{2}}}{{{B}^{2}}}\]
C) \[\frac{{{c}^{2}}}{{{C}^{2}}}\]
D) None of these
Correct Answer: B
Solution :
\[\frac{\alpha }{\beta }=\frac{\gamma }{\delta }.\]Apply C and D ; \[\frac{\alpha +\beta }{\alpha -\beta }=\frac{\gamma +\delta }{\gamma -\delta }\]Square both sides |
\[\therefore \frac{{{b}^{2}}}{{{b}^{2}}-4ac}=\frac{{{B}^{2}}}{{{B}^{2}}-4AC}\] \[\therefore \frac{{{D}_{1}}}{{{D}_{2}}}=\frac{{{b}^{2}}}{{{B}^{2}}}\Rightarrow (b)\] |
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