A) One
B) two
C) Three
D) four
Correct Answer: C
Solution :
[c] \[-13.6+12.1=\frac{-13.6}{{{n}^{2}}}\] \[\operatorname{or}n=3.\] The spectral lines corresponding to \[n=3\] Will be \[\frac{n(n-1)}{2}=\frac{3(3-1)}{2}=3\]You need to login to perform this action.
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