A) \[0.2\times {{10}^{-4}}\operatorname{tesla}\]
B) \[0.4\times {{10}^{-4}}\operatorname{tesla}\]
C) \[0.6\times {{10}^{-4}}\operatorname{tesla}\]
D) \[0.8\times {{10}^{-4}}\operatorname{tesla}\]
Correct Answer: D
Solution :
[d]Using, \[T=2\pi \sqrt{\frac{I}{M\,\,{{B}_{H}}}}\] |
\[\sqrt{10}=2\pi \sqrt{\frac{{{10}^{-5}}}{1\times {{B}_{H}}}}\] |
or \[10=4{{\pi }^{2}}\times \frac{{{10}^{-5}}}{B{{ & }_{H}}}\] |
or \[{{B}_{H}}=4\times {{10}^{-5}}T\] |
\[\therefore B=\frac{{{B}_{H}}}{\cos \theta }=\frac{4\times {{10}^{-5}}}{\cos 60{}^\circ }=0.8\times {{10}^{-4}}T\] |
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