A) \[\frac{mg}{k}\]
B) \[\frac{2mg}{k}\]
C) \[\frac{3mg}{k}\]
D) \[\frac{4mg}{k}\]
Correct Answer: A
Solution :
[B] Just after cutting the string extension in spring \[=\frac{3mg}{k}\] The extension in the spring when block is in mean position \[=\frac{mg}{k}\] \[\therefore \] Amplitude of oscillation \[A=\frac{3mg}{k}-\frac{mg}{k}=\frac{2mg}{k}.\]You need to login to perform this action.
You will be redirected in
3 sec