A) Zero
B) \[\frac{Qqd}{2\pi {{\in }_{0}}{{\ell }^{3}}}\]
C) \[\frac{Qqd}{\pi {{\in }_{0}}{{\ell }^{3}}}\]
D) \[\frac{Qqd}{4\pi {{\in }_{0}}{{\ell }^{3}}}\]
Correct Answer: A
Solution :
[B] The two plates acts as a dipole \[\therefore \]Force on charge q; \[F=Eq=\left( \frac{2kQd}{{{\ell }^{3}}} \right).q=\frac{Qqd}{2\pi {{\varepsilon }_{0}}{{\ell }^{3}}}.\]You need to login to perform this action.
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