A) \[1\Omega \]
B) \[2\Omega \]
C) \[3\Omega \]
D) \[4\Omega \]
Correct Answer: A
Solution :
[A]Current in the circuit is i and \[i=\frac{{{\in }_{eq}}}{R+{{r}_{eq}}}\] |
\[{{\in }_{eq}}=6+6=12,\] \[{{r}_{eq}}=3+2=5\] |
\[i=\frac{12}{R+5}\] |
p.d. across A=0 |
\[{{\in }_{A}}-i{{r}_{A}}=0,\] where \[{{\in }_{A}}=6V\] and \[{{r}_{A}}=3\Omega \] |
\[6-\frac{12}{R+5}\times 3=0\]\[R=1\Omega \] |
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