A) Zero
B) \[I\ell B\]
C) \[\sqrt{2}\,I\ell B\]
D) \[2\ell B\]
Correct Answer: C
Solution :
[C] \[{{F}_{PQ}}=0\Rightarrow {{F}_{QR}}=I\ell B\] \[{{F}_{RS}}=I\ell B\] \[{{F}_{QR}}\] & \[{{F}_{RS}}\] are perpendicular to each other \[\therefore {{F}_{net}}=\sqrt{{{(I\ell B)}^{2}}+{{(I\ell B)}^{2}}}=\sqrt{2}I\ell B\]You need to login to perform this action.
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