(a) Find the amount of Rs. 50000 after 2 years compounded annually. The rate of interest being 8% p.a. during the first year and 9% p.a. during the second year. Also, find the compound interest. |
(b) If (a) decreased value \[=P{{\left( 1-\frac{R}{100} \right)}^{n}}\] and (b) depreciated value \[=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] then select right answer. |
Answer:
(a) Here P=' 50000, \[{{R}_{1}}\] = 8% p.a. and \[{{R}_{2}}\] = 9% p.a Since, \[A=P\left( 1+\frac{{{R}_{1}}}{100} \right)\left( 1+\frac{{{R}_{2}}}{100} \right)\] \[=50000\times \left( 1+\frac{8}{100} \right)\left( 1+\frac{9}{100} \right)\] \[=50000\times \frac{27}{25}\times \frac{109}{100}\] Amount =Rs.58860 Therefore \[C.I.\text{ }=\text{ }A\text{ }-\text{ }P\] \[=58860-50000\] =Rs. 8860 (b) (a) is right answer.
You need to login to perform this action.
You will be redirected in
3 sec