Answer:
We have, the sum of the digits of 51x 3=5+l+x+3=9+x Since, 51x 3 is divisible by 9. \[\therefore \] (9+x) must be divisible by 9. \[\therefore \](9 + x) must be equal to 0 or 9 or 18 or 27 or... But x is a digit, then \[9+x=9\Rightarrow x=0\] \[9+x=18\Rightarrow x=9\] \[x=27\Rightarrow x=18,\]which is not possible. \[\therefore \] The required value of x = 0 or 9.
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