Answer:
Here, P = 12000, R = 6% p.a. T = 2 years S. I. = \[\frac{P\times R\times T}{100}\] \[=\frac{12000\times 6\times 2}{100}=Rs.\,1440\] Amount (A) \[=\text{ }P+S.I.=12000+1440\] =Rs. 13440 Again in second case, A = P\[{{\left( 1+\frac{R}{100} \right)}^{n}}\] \[=12000{{\left( 1+\frac{6}{100} \right)}^{2}}\] \[=12000{{\left( \frac{53}{50} \right)}^{2}}\] \[=12000\times \frac{53}{50}\times \frac{53}{50}\] = Rs.13483.20 I pay extra amount \[=\text{ }{{A}_{2}}{{A}_{1}}\] = Rs. 13483.20 - Rs.13440 = Rs. 43.20
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