Answer:
\[\frac{{{(-2)}^{3}}\times {{(-2)}^{7}}}{3\times {{4}^{6}}}=\frac{{{(-2)}^{3+7}}}{3\times {{({{2}^{2}})}^{6}}}\] \[=\frac{{{(-2)}^{10}}}{3\times {{(2)}^{12}}}\] \[=\frac{{{(-1)}^{10}}{{(2)}^{10}}}{3\times {{(2)}^{12}}}\] \[=\frac{1\times {{(2)}^{10-12}}}{3}\] \[=\frac{{{2}^{-2}}}{3}\] \[=\frac{1}{3\times {{2}^{2}}}\] \[=\frac{1}{12}\]
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