A) \[\frac{1}{3}(x-9)(x+3)\]
B) \[\frac{1}{3}(x-9)(x-3)\]
C) \[\frac{1}{3}(x+9)(x+3)\]
D) \[\frac{1}{3}(x+9)(x-3)\]
Correct Answer: A
Solution :
\[\left( \frac{1}{3}{{x}^{2}}-2x-9 \right)=\frac{({{x}^{2}}-6x-27)}{3}\] \[=\frac{1}{3}[{{x}^{2}}-9x+3x-27]\] \[=\frac{1}{3}[x(x-9)+3(x-9)]\] \[=\frac{1}{3}(x+3)(x-9)\]You need to login to perform this action.
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