A) \[x+y+5=0\]
B) \[x-y+1=0\]
C) \[x-y=5\]
D) None of these
Correct Answer: B
Solution :
Clearly, from the figure, the origin is contained in the angle. Writing the equations of the lines as \[2x-y+4=0\] and \[-x+2y+1=0,\]the required bisector is |
\[\frac{2x-y+4}{\sqrt{5}}=\frac{-x+2y+1}{\sqrt{5}}\] |
\[2x-y+4=-x+2y+1\] |
\[2x+x-y-2y+4-1=0\] |
\[3x-3y+3=0\]\[\Rightarrow \]\[x-y+1=0\] |
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