A) \[{{a}^{2}}+9a-20\]
B) \[{{a}^{2}}-9a+20\]
C) \[{{a}^{2}}+9a+20\]
D) \[{{a}^{2}}-9a-20\]
Correct Answer: C
Solution :
As we know, |
\[HCF\times LCM=\]Product of polynomials |
Let other polynomial be q(x). |
\[p\,\,(x)=({{a}^{2}}+4a-5)\] |
\[\therefore \]\[(a+5)(a+5)(a+4)(a-1)=({{a}^{2}}+4a-5)\,\,q\,\,(x)\] |
\[q\,\,(x)=(a+5)(a+5)\times \frac{(a+4)(a-1)}{(a+5)(a-1)}\] |
\[q\,\,(x)=(a+5)(a+4)={{a}^{2}}+9a+20\] |
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