A) 144 cm
B) \[72\sqrt{2}\,\,\text{cm}\]
C) \[144\sqrt{2}\,\,\text{cm}\]
D) None of these
Correct Answer: C
Solution :
Length of a diagonal of square \[=\frac{144}{2}=72\,\,\text{cm}\] |
Let side of square of 'a,' then |
\[{{a}^{2}}+{{a}^{2}}={{(72)}^{2}}\] |
\[2{{a}^{2}}={{(72)}^{2}}\] |
\[\Rightarrow \] \[\sqrt{2a}=72\]\[\Rightarrow \]\[a=\frac{72}{\sqrt{2}}\] |
\[\therefore \]The perimeter of square |
\[=4a=4\times \frac{72}{\sqrt{2}}=144\sqrt{2}\,\,\text{cm}\] |
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