A) 12 m/s
B) 10 m/s
C) 15 m/s
D) 20 m/s
Correct Answer: A
Solution :
In crossing a man standing on platform, train crosses its own length. \[\therefore \]Speed of train \[=\frac{120\,\,\text{m}}{10\,\text{s}}12\,\,\text{m/s}\]You need to login to perform this action.
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