A) 3
B) 4
C) 5
D) 6
Correct Answer: C
Solution :
\[x=1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}=1+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{3}{2}}}}\] \[=1+\frac{1}{1+\frac{1}{1+\frac{2}{3}}}=1+\frac{1}{1+\frac{1}{\frac{5}{3}}}=1+\frac{1}{1+\frac{3}{5}}\] \[=1+\frac{1}{\frac{8}{5}}=1+\frac{5}{8}=\frac{13}{8}\] \[\therefore \]\[2x+\frac{7}{4}=2\times \frac{13}{8}+\frac{7}{4}\] \[=\frac{13+7}{4}=\frac{20}{4}=5\]You need to login to perform this action.
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