A) 5
B) 12
C) 11
D) \[7+\sqrt{5}\]
Correct Answer: B
Solution :
The perimeter of \[\Delta AOB=d\,\,(AO)+d\,\,(OB)+d\,\,(AB)\] \[=4+3\sqrt{{{(4)}^{2}}+{{(3)}^{2}}}\]
\[=7\sqrt{16+9}=7+\sqrt{25}=7+5=12\]
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