A) 24 days
B) 32 days
C) 40 days
D) 48 days
Correct Answer: D
Solution :
(A + B)'s 1 day's work\[=\frac{1}{2}\] ?(i) |
(B + C)'s 1 day's work \[=\frac{1}{8}\] ?(ii) |
(C + A)'s 1 day's work \[=\frac{1}{6}\] ?(iii) |
On adding, 2 (A + B + C)'s 1 day's work |
\[=\frac{1}{12}+\frac{1}{8}+\frac{1}{6}\] |
\[=\frac{2+3+4}{24}=\frac{9}{24}\] |
\[\therefore \](A + B + C)'s 1 days? work |
\[=\frac{9}{24\times 2}=\frac{9}{48}\] ?(iv) |
On, subtracting Eq. (iii) from Eq. (iv), we get |
B?s 1 day's work \[=\frac{9}{48}-\frac{1}{6}=\frac{9-8}{48}=\frac{1}{48}\] |
\[\therefore \] B can complete the work in 48 days. |
You need to login to perform this action.
You will be redirected in
3 sec