A) 12
B) 13
C) 14
D) 15
Correct Answer: C
Solution :
Let the numbers be x and y. Then, \[{{x}^{2}}+{{y}^{2}}=100\] \[{{x}^{2}}-{{y}^{2}}=28\] On adding, \[2{{x}^{2}}=128\] \[\Rightarrow \] \[{{x}^{2}}=64\] \[\Rightarrow \] \[x=8\] From Eq. (i), \[64+{{y}^{2}}=100\] \[\Rightarrow \] \[{{y}^{2}}=36\] \[\Rightarrow \] \[y=6\] \[\therefore \] Required sum \[=8+6=14\]You need to login to perform this action.
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